if then else twice and if not found then run a command
by bmxakias from LinuxQuestions.org on (#4VCP1)
Hello
I have this code:
Code:if [[ $(find /path/to/folder1 -type f -not -path "*configs*" -size -800k 2>/dev/null) ]]; then
echo "[[Warning]]: The files size is under 800 Kilobytes"
if [[ $(find /path/to/another/folder -type f \( ! -iname "123.file*" \) -not -path "*logs*" -size -40k 2>/dev/null) ]]; then
echo "[[Warning]]: The file size is under 40 Kilobytes"
fi
else
Run a command here
fi
The target is:
Get an echo if a file under size found in any of the above paths or get both echo if a file under size found on both paths and run the command at the end only if not files under size found at any of the above two paths.
Both checks are tested and working but it seems that i have the if or else statements in wrong order ?
Thank you !
I have this code:
Code:if [[ $(find /path/to/folder1 -type f -not -path "*configs*" -size -800k 2>/dev/null) ]]; then
echo "[[Warning]]: The files size is under 800 Kilobytes"
if [[ $(find /path/to/another/folder -type f \( ! -iname "123.file*" \) -not -path "*logs*" -size -40k 2>/dev/null) ]]; then
echo "[[Warning]]: The file size is under 40 Kilobytes"
fi
else
Run a command here
fi
The target is:
Get an echo if a file under size found in any of the above paths or get both echo if a file under size found on both paths and run the command at the end only if not files under size found at any of the above two paths.
Both checks are tested and working but it seems that i have the if or else statements in wrong order ?
Thank you !