Bash logic combination to restrict a user to the required number of argument

My bash function is suppose to ask for an argument when it is not supplied and indicate surplus argument when the argument supplied is more than three (3). But presently,when i supply it with 3 argument it does not echo "surplus argument" but give the same result with when i supply one or two argument. Please how do i correct this or is it from my bash logic combination?
below is the code:

#!/bin/bash

Variable1="$1"
Variable2="$2"

AddVariable () {

Variable1="$1"
Variable2="$2"

if [ "$#" -eq 0 ]
then
echo "provide an argument"

elif [ "$#" -ne 1 ] && [ "$#" -ne 2 ] || [ "$#" -eq 3 ]
then
echo "Surplus argument provided"
else

printname "$Variable1"
deletename "$Variable2"

fi

}

deletename(){

for file in $Variable/*;do

echo "$(rm -i "$file")"
echo "deleting $Variable"

done
}
printname(){
Variable=$1
for file in $Variable/*;do

echo "$(basename "$file")"
done
}

#printname "$Variable1"
#deletename "$Variable2"
AddVariable $Variable1 $Variable2