bash command with arguments in variable
by blueray from LinuxQuestions.org on (#56GPS)
If I use export EDITOR="code" then run $EDITOR, It opens vscode.
However, If I use export EDITOR="code -n -w" then use $EDITOR, it says
Code:% $EDITOR
code -n -w: command not foundHow can I use code -n -w in $EDITOR so that it identifies it as a command.
However, If I use export EDITOR="code -n -w" then use $EDITOR, it says
Code:% $EDITOR
code -n -w: command not foundHow can I use code -n -w in $EDITOR so that it identifies it as a command.