Why for loop without any working code (in third part) is there?

In the link given here, in the main() there is twice given a for-loop, that has empty 3rd part, i.e. nothing gets executed.

Kindly help by telling why such for-loop was used twice.
The code is repeated below:

Code:#include <stdio.h>
#include <stdint.h>
#include <stdlib.h>
#define pcx putchar_unlocked
#define gcx getchar_unlocked

typedef int32_t ichar;
typedef int_fast64_t fint;

static inline fint getfi () {
ichar c = gcx();
while (!isdigit (c)) c = gcx();
fint n = 0;
while (isdigit (c)) {
n = n * 10 + c - '0';
c = gcx();
}
return n;
}

static inline void putfi (fint n, char lc) {
if (0 == n) {
pcx ('0');
if (lc) pcx (lc);
return;
}
char s[24];
fint rdi = 0;
while (n) {
s[rdi++] = '0' + n % 10;
n /= 10;
}
while (rdi) pcx (s[--rdi]);
if (lc) pcx (lc);
}

static inline fint min2 (fint A, fint B) {
return (A < B ? A : B);
}

int main () {
fint A [100000];
fint R [100000];
fint T = getfi() + 1;
while (--T) {
fint N = getfi();
for (fint ai = 0; ai < N; )
A[ai++] = N - getfi();
for (fint ri = N-1; ri >=0; )
R[ri--] = N - getfi();
char nlt[100008] = {0};
fint exit = 0;
for (fint ai = 0; ai < N; ++ai) {
A[ai] = A[ai] + R[ai] - N;
if (A[ai] < 1 || A[ai] > N) {
exit = 1;
break;
}
if (nlt[A[ai]]){
exit = 1; break;
}
else nlt[A[ai]] = 1;
}
if (exit) {
pcx('-');
pcx('1');
pcx('\n');
continue;
}
for (fint ai =0; ai < N; )
putfi(A[ai++], ' ');
pcx('\n');
}
return 0;
}