Article 7167H Impedance and Triangular Numbers

Impedance and Triangular Numbers

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John
from John D. Cook on (#7167H)

A few days ago I wrote two posts about how to create a Smith chart, a graphical device used for impedance calculations. Then someone emailed me to point out the connection between the Smith chart and triangular numbers.

The Smith chart is the image of a rectangular grid in the right half-plane under the function

f(z) = (z- 1)/(z+ 1).

If you subtract the values off at consecutive integers, you get the reciprocal of a triangular number.

f(n) -f(n - 1) = 2/(n(n + 1)) = 1 /Tn

Or to put it another way,

f(n) -f(n - 1) = 1 / (1 + 2 + 3 + ... + n).

In the first post on the Smith chart we showed that the functionf maps vertical lines

smithchart0.png

in thez plane to circles in thew plane all touching atw = 1.

smithchart1.png

The circles are symmetric about the real axis and the diameter runs fromf(n) to 1. The separation between the circles on the left side is thus

f(n) -f(n - 1) = 1 /Tn.

Number the circles starting from the outermost as 0, 1, 2, .... Then the maximum distance between circle n and circle n - 1 is 1 /Tn. You can see in the graph above that the distance between circle 0 and circle 1 is 1. It's a little harder to see that the distance between circle 1 and circle 2 is 1/3. It looks like the distance between circles 2 and 3 is about half of that between circles 1 and 2, so it would be 1/6.

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