Proportion of 1s in a Hadamard matrix
The first post in the recent series of posts on Hadamard matrices describes a way of constructing new Hadamard matrices from two other Hadamard matrices by taking their Kronecker product.
Starting with a Hadamard matrixH0 and a Hadamard matrix G, you can construct a sequence of Hadamard matrices by
Hn+1 = G Hn
for positive integers n. This is known as the generalized Sylvester method.
Let pn be the proportion of 1s in Hn and let q be the proportion of 1s in G. Then you can show that the recurrence holds
pn+1 = q pn + (1 - q)(1 - pn).
You can solve the recurrence to show that
limn pn =
and so as the iterations proceed, the ratio of number of 1s to the number of -1s approaches 1.
This doesn't say anything Hadamard matrices in general, but it does apply to all Hadamard matrices created by repeatedly applying the generalized Sylvester method.
If you setG andH equal to the matrix
thenp0 =q = 3/4. Then forn = 1, 2, 3, ..., 8 the values of pn are
0.625
0.5625
0.53125
0.515625
0.5078125
0.50390625
0.501953125
0.5009765625.