Article 77QRC Proportion of 1s in a Hadamard matrix

Proportion of 1s in a Hadamard matrix

by
John
from John D. Cook on (#77QRC)

The first post in the recent series of posts on Hadamard matrices describes a way of constructing new Hadamard matrices from two other Hadamard matrices by taking their Kronecker product.

Starting with a Hadamard matrixH0 and a Hadamard matrix G, you can construct a sequence of Hadamard matrices by

Hn+1 = G Hn

for positive integers n. This is known as the generalized Sylvester method.

Let pn be the proportion of 1s in Hn and let q be the proportion of 1s in G. Then you can show that the recurrence holds

pn+1 = q pn + (1 - q)(1 - pn).

You can solve the recurrence to show that

limn pn =

and so as the iterations proceed, the ratio of number of 1s to the number of -1s approaches 1.

This doesn't say anything Hadamard matrices in general, but it does apply to all Hadamard matrices created by repeatedly applying the generalized Sylvester method.

If you setG andH equal to the matrix

hadamard2.svg

thenp0 =q = 3/4. Then forn = 1, 2, 3, ..., 8 the values of pn are

0.625
0.5625
0.53125
0.515625
0.5078125
0.50390625
0.501953125
0.5009765625.

The post Proportion of 1s in a Hadamard matrix first appeared on John D. Cook.
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