Article 59F98 To have separator IFS on a condition

To have separator IFS on a condition

by
BudiKusasi
from LinuxQuestions.org on (#59F98)
Is there any way or workaround resorts to correctly have separator IFS on a condition that
it's a certain character only if not preceded by another certain character ?

Let e.g. separator must be `;` not being preceded by `\`
or e.g. separator must be `|` not being preceded by `\`

IFS= # ... ??
# ?latest?d=yIl2AUoC8zA latest?i=ogSQp9pkGGM:fZ8ss9xds3k:F7zBnMy latest?i=ogSQp9pkGGM:fZ8ss9xds3k:V_sGLiP latest?d=qj6IDK7rITs latest?i=ogSQp9pkGGM:fZ8ss9xds3k:gIN9vFwogSQp9pkGGM
External Content
Source RSS or Atom Feed
Feed Location https://feeds.feedburner.com/linuxquestions/latest
Feed Title LinuxQuestions.org
Feed Link https://www.linuxquestions.org/questions/
Reply 0 comments