Article 5KT7W How to find the URI and repository name from which the package was installed?

How to find the URI and repository name from which the package was installed?

by
verilog15
from LinuxQuestions.org on (#5KT7W)
Hello!
My task is to do the following: Build a script which, given a list of rpm packages, finds all the zypper repositories (name and URIs).

I have a package installed locally and I want to find the zypper URI and the repository name from which the package was installed from. I could search for the package and find it:
Code:zypper info $PKG_NAMEIt does give me the repo name (if there is one) but it does not give me the URI:
Code:> zypper info tcsh
Information for package tcsh:

Repository: <REPO_NAME>
Name: tcsh
Version: 6.18.01-9.7.1
Arch: x86_64
Vendor: SUSE LINUX Products GmbH, Nuernberg, Germany
Support Level: unknown
Installed: Yes
Status: up-to-date
Installed Size: 1.0 MiB
Summary: The C SHell
Description:
Tcsh is an enhanced, but completely compatible, version of the Berkeley
UNIX C shell, csh(1). It is a command language interpreter usable as an
interactive login shell and a shell script command processor. It
includes a command-line editor, programmable word completion, spelling
correction, a history mechanism, job control, and a C-like syntax.I want the "Repository:" part.

I'm also familiar with the Code:zypper repos -u command to list all the repositories and URIs.

I could combine the two commands and find the repository name and then the URI. Is there a better approach? My biggest struggle is on how to parse it. So the questions are:
1. Is there a command that given the package name, returns the repository name (without the need to parse)?
2. Is there a command that given the package name, returns the repository URI (without the need to parse)? Is it possible to combine it with question 1 and just get those two?
3. If there is no way to get the repository URI based on the package name, is there a command to get the repository URI based on the repository name (without the need to parse)?

Maybe this can be extract with RPM?latest?d=yIl2AUoC8zA latest?i=je_nKWw0-XU:E1T1dwU9NI4:F7zBnMy latest?i=je_nKWw0-XU:E1T1dwU9NI4:V_sGLiP latest?d=qj6IDK7rITs latest?i=je_nKWw0-XU:E1T1dwU9NI4:gIN9vFwje_nKWw0-XU
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