Article 6JX7B Determinant of an infinite matrix

Determinant of an infinite matrix

by
John
from John D. Cook on (#6JX7B)

What does the infinite determinant

infinite_det.svg

mean and when does it converge?

The determinant D above is the limit of the determinants Dn defined by

infinite_det2.svg

If all the as are 1 and all the bs are -1 then this post shows that Dn = Fn, the nth Fibonacci number. The Fibonacci numbers obviously don't converge, so in this case the determinant of the infinite matrix does not converge.

In 1895, Helge von Koch said in a letter to Poincare that the infinite determinant is absolutely convergent if and only if the sum

infinite_det4.svg

is absolutely convergent. A proof is given in [1].

The proof shows that the Dn are bounded by

infinite_det5.svg

and so the infinite determinant converges if the corresponding infinite product converges. And a theorem on infinite products says

infinite_det6.svg

converges absolute if the sum in Koch's theorem converges. In fact,

infinite_det7.svg

and so we have an upper bound on the infinite determinant.

Related post: Triadiagonal systems, determinants, and cubic splines

[1] A. A. Shaw. H. von Koch's First Lemma and Its Generalization. The American Mathematical Monthly, April 1931, Vol. 38, No. 4, pp. 188-194

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