by John on (#6B4Y3)
There is no polynomial with rational coefficients that evaluates to 0 at π. That is, π is a transcendental number, not an algebraic number. This post will prove this fact as a corollary of a more advanced theorem. There are proof that are more elementary and direct, but the proof given here is elegant. A […]The post Overpowered proof that π is transcendental first appeared on John D. Cook.