by John on (#6WY27)
In the previous post, I did a simulation to illustrate a theorem about the number of steps needed in the Euclidean algorithm. The distribution of the number of steps is asymptotically normal, and fornumbers 0 <a<b<x the mean is asymptotically 12 log(2) log(x) / ^2. What about the variance? The reference cited in the previous [...]The post Variance of variances. All is variance. first appeared on John D. Cook.